The Bohr method effectively takes advantage of the minimized mass of electron and proton in all cases, in lieu of the mass of the electron, Helium's Bohr product demonstrates that the primary two electrons are in the exact same Power level. But How about elements with a lot more electrons? http://umtsflatvergleich.de/die-vorteile-der-verwendung-einer-hebebuhne-in-ihrem-trainingsprogramm/